The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which
(a) an electron, and
(b) a neutron, would have the same de-Broglie wavelength.

Solution

Given,
Wavelength of sodium light, $λ$ = 589 nm

We know that, $λ = \frac{h}{\sqrt{2 mE}}$

$\Rightarrow$ $E = \frac{h^{2}}{2 λ^{2} m}$

(a) For electron,

Energy, $E = \frac{(6.63 \times 10^{- 34})^{2}}{2 \times (589 \times 10^{- 9})^{2} \times 9 \times 10^{- 31}}$

$= 7.03 \times 10^{- 25} J$

(b) For neutron,

Energy, $E = \frac{(6.63 \times 10^{- 34})^{2}}{2 \times (589 \times 10^{- 9})^{2} \times 1.66 \times 10^{- 27}}$

$= 3.81 \times 10^{- 28} J .$

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The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which
(a) an electron, and
(b) a neutron, would have the same de-Broglie wavelength.

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Wave Optics

The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which(a) an electron, and(b) a neutron, would have the same de-Broglie wavelength.

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which
(a) an electron, and
(b) a neutron, would have the same de-Broglie wavelength.