-->

Wave Optics

Question
CBSEENPH12038454

Light of frequency 7.21 x 1014 Hz is incident on a metal surface. Electrons with a maximum speed of 6.0 x 105 m/s are ejected from the surface. What is the threshold frequency for photoemission of electrons?

Solution

Given,
Frequency of light, ν = 7.21 x 1014 Hz
Maximum speed of electrons, vmax = 6.0 x 105 ms–1
Mass of the electron, m = 9 x 10–31 kg

Applying Einstein's photoelectric equation,
                K.E.max = 12mv2max = h(v-v0)

       12mv2max = h(v-v0)
                  v0  = v - mv2max2h
                              v0 = 7.21 × 1014 - (9.1 × 10-31) × (6 × 105)22 × (6.63 × 10-34)
                           = 4.74 × 1014Hz.

Some More Questions From Wave Optics Chapter