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Wave Optics

Question
CBSEENPH12038453

The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?

Solution
Work function of the metal, ɸ0 = 4.2 eV
                                               = 4.2 x 1.6 x 10
–19 J
                                               = 6.72 x10
–19 J 
Wavelength of incident radiation, λ = 330 nm 

Now, using the formula for energy of a photon, E = hcλ

       E = 6.62 × 10-34 × 3 × 108330 × 10-9        = 6.018 × 10-19J 

As energy of incident photon E < ɸ0, hence no photoelectric emission will take place.

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