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Wave Optics

Question
CBSEENPH12038333

A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes in a Young's double-slit experiment.
Find the distance of the third bright fringe on the screen from the central maximum for wavelength 650 nm.

Solution

Here,
Wavelength of the beam of light, λ1 = 650 nm = 650 × 10-9m
Wavelength of beam of light,  λ2 = 520 nm = 520 × 10-9 m

Suppose, 
d = distance between two slits and, 
D is the distance between the screen and slit. 

For third bright fringe, n = 3
Distance of third bright fringe from the central maximum, x =n.λ1.Dd
                    = 3 × 650 × 10-7 × 1200.2= 0.117 cm = 1.17 mm