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Wave Optics

Question
CBSEENPH12038331

In a Young's double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 m. Determine the wavelength of light used in the experiment.

Solution

Given,
Distance between the screen and slits, D = 1.4 m,   Distance between slits, d = 0.28 mm =0.28 × 10-3 m 

Fringe width,ω = 1.24 = 0.3 × 10-2m   (as the distance 1.2 m is of fourth fringe from central maxima)

Using formula, we have 

Fringe width, ω = d 
  λ = ωdD    = 0.3 × 10-2 × 0.28 × 10-31.4   = 0.06 × 10-5    = 600 × 10-9    = 600 nm.  

which is the required wavelength.