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Wave Optics

Question

A slit of width 3 mm is illuminated by light of λ= 600 nm at normal incidence. If the distance of the screen from the slit is 60 cm, calculate the distance between the first order minimum on both sides of central maximum.

Solution

Given,
Distance between the slits, d = 3 mm = 3 × 10^-3 m
Wavelength of light, λ = 600 nm = 6 × 10^-7 m
Distance between the slit and the screen, D = 60 cm = 0.60 m

Distance of first order minima from central maximum is,
$x_{n} = n \frac{λD}{d} x_{1} = 1 \times \frac{λD}{d}$

Therefore, distance between first order minimum on both sides of the central maximum is,

$2 x_{1} = \frac{2 λD}{d}$
$\Rightarrow$ $2 x_{1} = \frac{2 \times 6 \times 10^{- 7} \times 0.6}{3 \times 10^{- 3}}$
$= 0.24 \times 10^{- 3} m or 0.24 mm .$

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Wave Optics

A slit of width 3 mm is illuminated by light of λ= 600 nm at normal incidence. If the distance of the screen from the slit is 60 cm, calculate the distance between the first order minimum on both sides of central maximum.

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