If the angle between the pass axis of polarizer and the analyser is 45°, write the ratio of the intensities of original light and the transmitted light after passing through the analyser.

Solution

Given,
Angle between pass axis of polarizer and analyser, $θ = 45 °$

Using formula,
   $I = I_{0} \cos^{2} θ$

$\Rightarrow$ $I = I_{0} (\cos 45 °)^{2}$

$\Rightarrow$    $I = I_{0} {(\frac{1}{\sqrt{2}})}^{2}$

$\Rightarrow$    $\frac{I}{I_{0}} = \frac{1}{2}$

i.e., $I : I_{0} = 1 : 2 .$

is the required ratio of intensities of original light and transmitted lightafter passing through the analyzer.

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Wave Optics

If the angle between the pass axis of polarizer and the analyser is 45°, write the ratio of the intensities of original light and the transmitted light after passing through the analyser.

Some More Questions From Wave Optics Chapter

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