A converging lens of refractive index 1.5 is kept in a liquid medium having same refractive index. What would be the focal length of the lens in this medium?

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Solution

Refractive index of the lens = 1.5 = Refractive index of medium.

The lens in the liquid will act like a plane sheet of glass.

∴ Its focal length will be infinite (∞)

By using the formula of lens maker,

\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})

\frac{1}{f} = (\frac{μ_{2}}{μ_{1}} - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})

μ_{1} = μ_{2}

∴

\frac{1}{f} = 0

Thus,

f = \infty .

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Wave Optics

A converging lens of refractive index 1.5 is kept in a liquid medium having same refractive index. What would be the focal length of the lens in this medium?

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