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Wave Optics

Question

Wired Faculty App

What is the height of the final image of the tower if it is formed at 25 cm?

Solution

Given,
Focal length of the eye-piece, f_e = 5 cm
Magnification produced by eyepiece, m

= 1 + \frac{D}{f_{e}} = 1 + \frac{25}{5} = 6

∴

Height of final image =

4.7 \times 6 = 28.2 cm .

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