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Wave Optics

Question

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What is the height of the final image of the tower if it is formed at 25 cm?

Solution

Given,
Focal length of the eye-piece, f_e = 5 cm
Magnification produced by eyepiece, m

= 1 + \frac{D}{f_{e}} = 1 + \frac{25}{5} = 6

∴

Height of final image =

4.7 \times 6 = 28.2 cm .

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