At what distance should the lens be held from the figure in Question 9.29 in order to view the squares distinctly with the maximum possible magnifying power?

Solution

Maximum magnifying power is obtained when the image is at the near point (25 cm).

Thus,
Image distance, v = -25 cm
Focal length, f = + 10 cm
Object distance, u = ?

Using the formula ,

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

∴

\frac{1}{u} = \frac{1}{v} - \frac{1}{f}

= \frac{1}{- 25} - \frac{1}{10} = \frac{- 2 - 5}{50} = \frac{- 7}{50}

i.e.,

u = - \frac{50}{7} = - 7.14 cm .

So the lens should be held at a distance of 7.14 cm away so as to have a maximum possible magnifying power.

For Daily Free Study Material Join wiredfaculty

Wave Optics

At what distance should the lens be held from the figure in Question 9.29 in order to view the squares distinctly with the maximum possible magnifying power?

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction