Question
A convex lens of crown glass (μg = 1.5) has a focal length of 15 cm. The lens is placed in (a) water (μw = 1.33) and (b) carbon bisulphide (μc = 1.65). Determine in each case, whether the lens behaves as a converging or diverging lens and determine its focal length.
Solution
Given,
Refractive index of crown glass = 1.5
Focal length of glss = 15 cm
Refractive index of water = 1.33
Refractive index of carbon bisulphide = 1.65
For lens in glass,
For lens in water,
For lens in carbon bisulphide,
...(iii)
Dividing (i) by (ii), we get
Focal length of lens when placed in water, fw = – 58.7 cm.
The positive sign indicates that the lens is converging.
Dividing (i) by (iii), we get
Focal length of lens when placed in carbon bi-sulphide, fe = – 82.5 cm.
The negative sign indicates that the lens behaves as a diverging lens when it is immersed in carbon bisulphide.
Refractive index of crown glass = 1.5
Focal length of glss = 15 cm
Refractive index of water = 1.33
Refractive index of carbon bisulphide = 1.65
For lens in glass,
For lens in water,
For lens in carbon bisulphide,
...(iii)
Dividing (i) by (ii), we get
Focal length of lens when placed in water, fw = – 58.7 cm.
The positive sign indicates that the lens is converging.
Dividing (i) by (iii), we get
Focal length of lens when placed in carbon bi-sulphide, fe = – 82.5 cm.
The negative sign indicates that the lens behaves as a diverging lens when it is immersed in carbon bisulphide.