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Wave Optics

Question
CBSEENPH12038273

A convex lens of crown glass (μg = 1.5) has a focal length of 15 cm. The lens is placed in (a) water (μw = 1.33) and (b) carbon bisulphide (μc = 1.65). Determine in each case, whether the lens behaves as a converging or diverging lens and determine its focal length.

Solution
Given,
Refractive index of crown glass = 1.5
Focal length of glss = 15 cm 
Refractive index of water = 1.33
Refractive index of carbon bisulphide = 1.65 

For lens in glass, 

115 =(μ-1) 1R1-1R2
       = (1.5 -1 ) 1R1-1R2= 0.5 1R1-1R2                                    ...(i)

For lens in water, 
     1fw =μg-μwμw 1R1-1R2        = 1.5-1.331.33 1R1-1R2         = 0.171.331R1-1R2                                       ...(ii)

For lens in carbon bisulphide, 

1fc = μg-μcμc 1R1-1R2
     = 1.5-1.651.651R1-1R2
     = -0.151.651R1-1R2                          ...(iii) 

Dividing (i) by (ii), we get 

Focal length of lens when placed in water, f
w = – 58.7 cm.
The positive sign indicates that the lens is converging. 

Dividing (i) by (iii), we get
Focal length of lens when placed in carbon bi-sulphide, fe = – 82.5 cm.
The negative sign indicates that the lens behaves as a diverging lens when it is immersed in carbon bisulphide.
 

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