A compound microscope with an objective of 1.0 cm focal length and an eyepiece of 2.0 cm focal length has a tube length of 20 cm. Calculate the magnifying power of microscope, if the final image is formed at the near point of the eye.

Solution

Here we are given a compound microscope.
Length of the tube, l = 20 cm
Near point, D = 25 cm
Focal length of objective, f₀ = 1 cm and,
Focal length of eye-piece, f_e = 2

Magnifying powe of objective,

m_{0} = \frac{l}{f_{0}} = \frac{20}{1} = 20

Magnifying power of eyepiece,

m_{e} = \frac{D}{f_{0}} = \frac{25}{2}

Therefore, magnifying power of microscope,

m = m_{0} m_{e} = 20 \times \frac{25}{2} = 250 .

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Wave Optics

A compound microscope with an objective of 1.0 cm focal length and an eyepiece of 2.0 cm focal length has a tube length of 20 cm. Calculate the magnifying power of microscope, if the final image is formed at the near point of the eye.

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