The oscillating electric field of an electromagnetic wave is given by:
E_y = 30 sin [2 × 10¹¹ t + 300 $π$ x] Vm^-1
Obtain the value of the wavelength of the electromagnetic wave.

Solution

Oscillating electric field is given by,

$E_{y} = 30 \sin [2 \times 10^{11} t + 300 πx] {Vm}^{- 1}$

On comparing the above equation with $E_{x} = E_{o} \sin (kz - ωt)$ we get,

$K = 300 π = \frac{2 π}{λ} \Rightarrow λ = \frac{1}{150} = 6.7 \times 10^{- 3} m$

which is the required value of the wavelength.