If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.48 x 10⁶ m and radius of lunar orbit is 3.8 x 10⁸ m.

Solution

Given,
Diameter of moon = 3.48 x 10⁶ m
Radius of lunar orbit, r = 3.8 x 10⁸ m
Focal length of objective, f_o = 15 cm

If d is diameter of the image, then
Angle subtended by diameter of moon $= \frac{3.48 \times 10^{6}}{3.8 \times 10^{8}}$
and,

Angle subtended by image $= \frac{d}{f_{0}} = \frac{d}{15}$
$∴$ $\frac{d}{15} = \frac{3.48 \times 10^{6}}{3.8 \times 10^{8}}$

Therefore,
Diameter of the image of the moon formed by objective lens, $d = \frac{3.48 \times 15 \times 10^{- 2}}{3.8}$
$= 13.73 \times 10^{- 2} m = 13.73 cm .$

For Daily Free Study Material Join wiredfaculty

Wave Optics

If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.48 x 10⁶ m and radius of lunar orbit is 3.8 x 10⁸ m.

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Location

For Daily Free Study Material Join wiredfaculty

Wave Optics

If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.48 x 106 m and radius of lunar orbit is 3.8 x 108 m.

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.48 x 10⁶ m and radius of lunar orbit is 3.8 x 10⁸ m.