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Current Electricity

Question

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A radio transmitter operates at a frequency of 880 kHz, and a power of 10 kW. Find the number of photons per second emitted.

Solution

Frequency of radio transmitter = 880 kHz
Power, P = 10 kW
Therefore,
Number of photons is given by,

n = \frac{P}{hv} = \frac{10 \times 10^{3}}{6.6 \times 10^{- 34} \times 880 \times 10^{3}}

= 1.171 \times 10^{31}

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