The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B₀ = 510 nT. What is the amplitude of the electric field part of the wave?

Solution

Given,
   $Amplitude of magnetic field, B_{0} = 510 nT = 510 \times 10^{- 9} T$
Speed of EM wave, $C = 3 \times 10^{8} m s^{- 1}$

For electromagnetic waves,
$C = \frac{E_{0}}{B_{0}}$

i.e.,    $E_{0} = C B_{0}$

   $= 3 \times 10^{8} \times 510 \times 10^{- 9} = 153 {NC}^{- 1}$

which is the required amplitude of electric field.

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The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B₀ = 510 nT. What is the amplitude of the electric field part of the wave?

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Current Electricity

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?

Some More Questions From Current Electricity Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B₀ = 510 nT. What is the amplitude of the electric field part of the wave?