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Electrostatic Potential And Capacitance

Question
CBSEENPH12038058

Obtain the resonant frequency and Q-factor of a series LCR circuit with L = 3.0 H, C = 27 μF, and R = 7.4 Ω. It is desired to improve the sharpness of the resonance of the circuit by reducing its 'full width at half maximum' by a factor of 2. Suggest a suitable way.

Solution

Given, 

Inductance, L = 3.0 H
Capacitance, C = 27 μF = 27 × 10-6F
Resistance, R = 7.4 Ω 

Therefore,
Resonant frequency,

ωr = 1LC      = 13.0 ×27 × 10-6 = 111 rad s-1 

Q-factor of the circuit, 

Q = ωrLR = 111 × 3.07.4 = 45 

For improvement in sharpness of resonance by a factor of 2, Q should be doubled. To double Q with changing ωr, R should be reduced to half, i.e., to 3.7 Ω.

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