A transformer with efficiency 80% works at 4 KW and 100 V. If the secondary voltage is 200 V. Then what will be primary and secondary currents?

Solution

Given,
Efficiency of the transformer, $η$ = 80 %
Power, P = 4 kW
Voltage across primary , E_P = 100 V
Voltage across seconadry , E_s = 200 V

E_P I_P = 4 kW = 4000 W
Now,
Current across the primary coil, I_P = $\frac{E_{P} I_{P}}{E_{P}} = \frac{4000}{100} = 40 A$

Using the formula for the efficiency of transformer,
   $η = \frac{E_{s} I_{s}}{E_{P} I_{P}}$

$\Rightarrow$    $\frac{80}{100} = \frac{200 I_{S}}{4000} = \frac{I_{s}}{20}$

$\Rightarrow$    $I_{S} = \frac{20 \times 80}{100} = 16 A$

which is the current across the secondary coil of the transformer.

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Electrostatic Potential And Capacitance

A transformer with efficiency 80% works at 4 KW and 100 V. If the secondary voltage is 200 V. Then what will be primary and secondary currents?

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