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Electrostatic Potential And Capacitance

Question

In an a.c. circuit the voltage applied is E = E₀ sin ωt. The resulting current in the circuit is I = I₀ sin $(ωt - π / 2) .$ What will be the power consumption in the circuit?

Solution

On comparing the two equations we can see that, phase difference between current and voltage is $π / 2$ .
Therefore, the power consumption in the circuit is 0. [ because, cos $π / 2 = 0]$

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Electrostatic Potential And Capacitance

In an a.c. circuit the voltage applied is E = E₀ sin ωt. The resulting current in the circuit is I = I₀ sin $(ωt - π / 2) .$ What will be the power consumption in the circuit?

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Electrostatic Potential And Capacitance

In an a.c. circuit the voltage applied is E = E0 sin ωt. The resulting current in the circuit is I = I0 sin (ωt - π/2). What will be the power consumption in the circuit?

Some More Questions From Electrostatic Potential and Capacitance Chapter

Mock Test Series

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Entrance Exams Preparation

In an a.c. circuit the voltage applied is E = E₀ sin ωt. The resulting current in the circuit is I = I₀ sin $(ωt - π / 2) .$ What will be the power consumption in the circuit?