A potential of E = 50 sin $(200 πt + \frac{π}{4})$ is applied across a resistor of 10 $Ω$ resistance. Find
(i) rms value of potential
(ii) frequency of a.c
(iii) initial phase
(iv) rms value of current

Solution

Given, E = 50 sin $(200 πt + \frac{π}{4})$
Resistance , R = 10 $Ω$

(i) Rms value of the potential,
$E_{RMS} = \frac{E_{0}}{\sqrt{2}} = \frac{50}{\sqrt{2}} = 25 \sqrt{2} V$

(ii) Frequency of a.c. supply,
$v = \frac{ω}{2 π} = \frac{200 π}{2 π} = 100 Hz$

(iii) Initial phase $= \frac{π}{4}$ ( from the given equation)

(iv) Rms value of current,

$I_{RMS} = \frac{1}{\sqrt{2}} \frac{E_{0}}{R} = \frac{1}{\sqrt{2}} \times \frac{50}{10} = 5 \sqrt{2} A$

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Electrostatic Potential And Capacitance

A potential of E = 50 sin $(200 πt + \frac{π}{4})$ is applied across a resistor of 10 $Ω$ resistance. Find
(i) rms value of potential
(ii) frequency of a.c
(iii) initial phase
(iv) rms value of current

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A potential of E = 50 sin $(200 πt + \frac{π}{4})$ is applied across a resistor of 10 $Ω$ resistance. Find
(i) rms value of potential
(ii) frequency of a.c
(iii) initial phase
(iv) rms value of current