(i) State the law that gives the polarity of the induced emf.
(ii) A 15.0 μF capacitor is connected to 220 V, 50 Hz source. Find the capacitive reactance and the rms current.

Solution

(i) The law that gives the polarity of induced emf is given by, Faraday's law of electromagnetic inductionwhich states that :
→ Induced e.m.f. is produced whenever magnetic flux linked with a circuit changes.
→ As long as the change in the magnetic flux continues, the induced e.m.f. lasts.
→ The magnitude of the induced e.m.f. is directly proportional to the rate of change of the magnetic flux linked with the circuit.

(ii) Given,
Capacitance, C = 15.0 μF = 15 × 10^–6

$Effective voltage, V = 220 V Frequency of the AC supply, f = 50 Hz$

Capacitive reactance,    $X_{C} = \frac{1}{2 πfc}$

   $X_{C} = \frac{1}{2 \times 3.14 \times 50 \times 15 \times 10^{- 6}}$

   $= \frac{10^{6}}{314 \times 15} = \frac{1000000}{4710} = 212.31 Ω$

Rms value of current is ,

$I_{rms} = \frac{V}{X_{C}} = \frac{220}{212.31} = 1.03 A .$

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Electrostatic Potential And Capacitance

(i) State the law that gives the polarity of the induced emf.
(ii) A 15.0 μF capacitor is connected to 220 V, 50 Hz source. Find the capacitive reactance and the rms current.

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Electrostatic Potential And Capacitance

(i) State the law that gives the polarity of the induced emf.(ii) A 15.0 μF capacitor is connected to 220 V, 50 Hz source. Find the capacitive reactance and the rms current.

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Mock Test Series

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(i) State the law that gives the polarity of the induced emf.
(ii) A 15.0 μF capacitor is connected to 220 V, 50 Hz source. Find the capacitive reactance and the rms current.