-->

Electrostatic Potential And Capacitance

Question

When a lamp is connected to an alternating voltage supply, if lights with the same brightness as when connected to a 12 V DC battery. What is the peak value of alternating voltage source?

Solution

Given,
Rms value of voltage, $V_{rms} = 12 V$
Effective voltage, $V_{eff .} = V_{rms} = \frac{V_{0}}{\sqrt{2}}$
So,
Peak voltage, $V_{0} = \sqrt{2} V_{rms} = 1.414 \times 12 = 16.97 V .$

For Daily Free Study Material Join wiredfaculty

Electrostatic Potential And Capacitance

When a lamp is connected to an alternating voltage supply, if lights with the same brightness as when connected to a 12 V DC battery. What is the peak value of alternating voltage source?

Some More Questions From Electrostatic Potential and Capacitance Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction