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Electrostatic Potential And Capacitance

Question

Suppose the initial charge on the capacitor in Question 7.7 is 6 mC. What is the total energy stored in the cirucit initially? What is the total energy at later time?

Solution

Given, initial charge in capacitor = 6 mC = 6 $\times 10^{- 3} C$

Since,
Energy of capacitor = $E = \frac{1}{2} \frac{Q^{2}}{C}$

$\Rightarrow$ $E = \frac{1}{2} \times \frac{{(6 \times 10^{- 3})}^{2}}{30 \times 10^{- 6}}$

$= \frac{36}{60} = 0.6 J .$

Since, energy is not absorbed by capacitor, there is no loss of energy. Therefore, the total energy remains the same.

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Electrostatic Potential And Capacitance

Suppose the initial charge on the capacitor in Question 7.7 is 6 mC. What is the total energy stored in the cirucit initially? What is the total energy at later time?

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