Electrostatic Potential And Capacitance

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Obtain the resonant frequency ω_r of a series LCR circuit with L = 2.0H, C = 32 μF and R = 10 Ω. What is the Q-value of this circuit?

Solution

Here,
Inductance, L = 2.0 H
Capacitance, $C = 32 μF = 32 \times 10^{6} F$
Resistance, R = 10 Ohm

Inductive reactance,

$ω_{r} = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{2.0 \times 32 \times 10^{- 6}}} = \frac{10^{3}}{8} = 125 rad / s Q - value of the circuit is, Q = \frac{1}{R} \sqrt{\frac{L}{C}} = \frac{1}{10} \sqrt{\frac{2}{32 \times 10^{- 6}}} = \frac{1000}{40} = 25 .$

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Electrostatic Potential And Capacitance

Obtain the resonant frequency ω_r of a series LCR circuit with L = 2.0H, C = 32 μF and R = 10 Ω. What is the Q-value of this circuit?

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Electrostatic Potential And Capacitance

Obtain the resonant frequency ωr of a series LCR circuit with L = 2.0H, C = 32 μF and R = 10 Ω. What is the Q-value of this circuit?

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Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Obtain the resonant frequency ω_r of a series LCR circuit with L = 2.0H, C = 32 μF and R = 10 Ω. What is the Q-value of this circuit?