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Current Electricity

Question
CBSEENPH12037917

In a power station, a copper bar designed to carry many amperes of current is 2 m long and 10 cm2 in cross-section. Determine the resistance of the bar at 0 °C. What potential difference is needed to cause a current of 5000 A through the bar? The resistivity of copper at 0°C is 1.59 x 10–8 Ω m. Also compute the resistance of the bar if it is stretched to form a long and uniform wire of 1 mm2 cross-section.

Solution
Length of the copper bar, l = 2m 
Area of cross-section of the bar, A=10 cm= 10× 10-4 m2 = 103 m2
Current across the bar, I = 5000 A 
Resistivity of Copper at 0o C, ρ = 1.59 x 10–8 Ω m
The resistance of the bar is given by,
               
                  R = ρlA  = 1.59 × 10-8 ×210-2= 3.18 × 10-5 Ω  

Now, using Ohm's law, the potential difference across its ends is
               V = I R = 5000 × 3.18 × 10-5 = 0.159 V  

Volume of the bar = A.l = 2 x 10–3 m

If the bar is stretched to form a long and uniform wire then, 

Area of cross-section of the wire = 1 mm2 = 10–6 m2
Length of wire, l

                      volumearea = 2×10-31×10-6= 2×103m 

The wire has the same amount of copper as the bar, but it is 2000 m long.
Therefore, the resistance of the wire is
                  R = ρlA     = 1.59 × 10-8×200010-6    =31.8 Ω