Three resistors of values 4 ohm, 6 ohm and 7 ohm are in series and a potential difference of 34 V is applied across the grouping. Find the potential drop across each resistor.

Solution

Given,
A potential difference of 34 V is applied across 3 resistors of 4

Ω

, 6

Ω

and 7

Ω

which are, grouped in series combination.

The current through the circuit, I is

I

= \frac{34}{(4 + 6 + 7)} = 2 A

Now,
Potential difference across 4

Ω

resistor = IR = 2x4 = 8 V
Potential difference across 6

Ω

resistor = 2x6 = 12 V
Potential difference across 7

Ω

resistor = 2x 7 = 14 V

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