-->

Current Electricity

Question
CBSEENPH12037908

Find the equivalent resistance of the circuit given across ab.


Solution
The circuit given may be redrawn as follows: 

 

In the left block, the resistance 5 ohm and 10 ohm is in series and the 25 ohm resistance is connected parallely to the series combination. 
Therefore, the equivalent resistance is, 

          25 × 1525 +15 = 9.4 Ω
Considering the right block,
We have 5 ohm and 5 ohm in series combination and 20 ohm is connected in parallel to the series combination.
Therefore, the equivalent resistance is, \

             10 × 2010 +20 = 20030 = 6.7 Ω 

The circuit now reduces as two resistors in series. 

 
Thus, effective resistance is given by, 
 R= 9.4 + 6.7
   = 16.1 Ω