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Electric Charges And Fields

Question
CBSEENPH12037892

Self-induction of an air core inductor increases from 0.01 mH to 10 mH on introducing an iron core into it. What is the relative permeability of the core used?

Solution
Here,
Initial self inducatnce, L
0 = 0.01 mH = 10–5 H
Final self inductance, L = 10 mH = 10–2 H 

Relative permeability is given by,

                   μr = LL0     = 10-210-5     = 103 =1000