Question
A toroidal solenoid with an air core has an average radius of 0.15 m, area of cross-section 12 x 10–4 m2 and 1200 turns. Obtain the self-inductance of the toroid. Ignore field variation across the cross-section of the toroid.
Solution
(a) Given, a toroidal solenoid.
Average radius, r = 0.15 m
Area of cross-section, A = 12 x 10–4 m2
Number of turns in the coil, n = 1200
Magnetic field is given by,
Total magnetic flux,
But,
(b) Emf induced,
where, Φ2 is the total magnetic flux linked with the second coil.
Thus,
= 0.023 V
where, Φ2 is the total magnetic flux linked with the second coil.
Thus,
= 0.023 V