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Electric Charges And Fields

Question
CBSEENPH12037890

A coil ACD of N turns and radius R carries a current I ampere and is placed on a horizontal table. K is a small conducting ring of radius r placed at a distance yo from the centre of and vertically above the coil ACD. Find an expression for the flux . 


Solution
We have a coil ACD of N turns and radius R carrying current I Ampere and, also a conducting ring K of radius 'r'.
Distance between ring and coil ACD = yo 

The field along the axis of the coil ACD is given by
                   μ04π.2π nIR2R2+yo23/2 

Since, the ring is small it may be assumed that the induction through it is uniform and is equal to that on the axis. 

The magnetic flux linked with it is
            ϕ = BA   = μ04π. 2π nIR2R2+yo23/2×πr2   = μ02. πnIR2r2R2+yo23/2.