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Electric Charges And Fields

Question
CBSEENPH12037878

A coil of inductance 2 mH carrying a current 2A is given. If the current is reversed in 0.01 seconds, how much back e.m.f. is produced?

Solution
Given, 

Self inductance, L = 2 mH
Current carried by the coil, I = 2 A

The current reverses in 0.01 s, this means the time period is 0.01/2 = 0.005 s. 

Therefore,
Induced EMF,       ε = -LdIdt
                            = 2 × 10-3 × 20.005= 0.8 V 

Induced emf is also called as the back emf because it opposes any change in current assosciated with the coil.