Question
The figure shows two identical rectangular loops (1) and (2) placed on a table along with a straight long current carrying conductor between them.
(i) What will be the directions of the induced currents in the loops when they are pulled away from the conductor with same velocity v?
(ii) Will the e.m.f. induced in the two loops be equal? Justify your answer.
Solution
(i) The direction of induced current will be such that it tends to maintain the original flux. Therefore, the direction of induced current is anticlockwise in loop 1 and clockwise in loop 2.
(ii) No, the emfs induced in the two loops will not be equal.
Since, the rate of change of flux is more in the second coil, emf induced in the second coil is more than that in the first coil.
Emf in the first coil, E1 = Bav
Emf in the second coil, E2 = Bbv
Since, b > a therefore, E2 > E1
(ii) No, the emfs induced in the two loops will not be equal.
Since, the rate of change of flux is more in the second coil, emf induced in the second coil is more than that in the first coil.
Emf in the first coil, E1 = Bav
Emf in the second coil, E2 = Bbv
Since, b > a therefore, E2 > E1
