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Electric Charges And Fields

Question
CBSEENPH12037869

A jet plane is travelling west at 450 m/s. If the horizontal component of earth's magnetic field at that place is 4 x 10–4 tesla and the angle of dip is 30°, find the emf induced between the ends of wings having a span of 30 m. 

Solution
Here,
Velocity of jet plane, v = 450 m/s
Length of the jet wing, l = 30 m
Horizontal component of Earth's magnetic field, B = 4 x 10
–4 T
Angle of dip, θ = 30° 

Using the formula for induced e.m.f we have,

Induced e.m.f,  ε = B l ν sin θ
                         = 4 × 10-4×30×450 = 5.4 V 

The direction of the wing does not affect this e.m.f.