Question
(a) Obtain an expression for the mutual inductance between a long straight wire and a square loop of side a as shown in Fig.
(b) Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, v = 10 m/s; calculate the induced emf in the loop at the instant when x = 0.2m. Take a = 0.1 m and assume that the loop has a large resistance.
Solution
Consider, a strip of width dx (of the square loop) at a distance x from the wire carrying current.
Magnetic field due to current carrying wire at a distance x from the wire is
Small amount of magnetic flux associated with the strip
Magnetic flux linked with the square loop
Since, Flux, we have
which is the required expression for the mutual inductance between a long straight wire and square loop of side a .
b) Given,
Current carried by the straight wire, I = 50 A
Velocity, v = 10 m/s
x = 0.2 m
Thus,
Induced emf in the loop
Magnetic field due to current carrying wire at a distance x from the wire is
Small amount of magnetic flux associated with the strip
Magnetic flux linked with the square loop
Since, Flux, we have
which is the required expression for the mutual inductance between a long straight wire and square loop of side a .
b) Given,
Current carried by the straight wire, I = 50 A
Velocity, v = 10 m/s
x = 0.2 m
Thus,
Induced emf in the loop