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Electric Charges And Fields

Question

Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average e.m.f. of 200 V induced, give an estimate of the self-inductance of the circuit?

Solution

Here,
Initial current, I₁ = 5 A
Final current, I₂ = 0 A
$∆$ t = 0.1 sec
Average emf, e= 200 V

Change in the value of current, dI/dt is,

$\frac{dI}{dt} = \frac{(I_{2} - I_{1})}{t} = \frac{0.0 - 5.0}{0.1} = - 50 {As}^{- 1}$

$A s, |e| = L |\frac{d I}{d t}|$
Therefore,
$L = \frac{|e|}{|dI / dt|} = \frac{200}{50} = 4 H .$

which is the required self inductance of the circuit.

Some More Questions From Electric Charges and Fields Chapter

Figure shows tracks of three charged particles in a uniform electrostatic field. Give the signs of the three charges. Which particle has the highest charge to mass ratio?

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Electric Charges And Fields

Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average e.m.f. of 200 V induced, give an estimate of the self-inductance of the circuit?

Some More Questions From Electric Charges and Fields Chapter

Figure shows tracks of three charged particles in a uniform electrostatic field. Give the signs of the three charges. Which particle has the highest charge to mass ratio?

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