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Electric Charges And Fields

Question
CBSEENPH12037855

A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s–1 in a uniform horizontal magnetic field of magnitude 3 x 10–2 T. Obtain the maximum and average e.m.f. induced in the coil. If the coil forms a closed loop of resistance 10 Ω, calculate the maximum value of current in the coil. Calculate the average power loss due to Joule heating. Where does this power come from?

Solution
Given,
Radius of the coil, r = 8 cm
Number of turns in the coil, N = 20 
Therefore, flux through each turn,
                     ϕ = BA     = BA cos θ  

                            ϕ = Bπr2 cos(ωt)  

For N turns,  ϕT = NB πr2 cos(ωt)

Thus, induced e.m.f, ε = Tdt
                                 = dNB πr2 cos(ωt)dt
                              ε = Tdt
                                  = dN B πr2 cos(ωt)dt
                              ε = NB πr2 ω sin(ωt) 

The maximum e.m.f,
            ε0 = NB πr2 ω      =20×50×π×64×10-4×3.0×10-2
                = 0.603 V                            

The average e.m.f, over a cycle  = 0
Resistance of the closed loop formed by the coil, R = 10 Ω
The maximum current, 

                 I0 = εR = 0.60310 = 0.0603 A

Power loss,

P = 12E0I0    = 12×0.603×0.0603   = 0.018 W 

The induced current causes a restoring torque in the coil. An external source is responsible for the supply of energy for this torque. So we can say that source of this power is the external rotor.