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Electric Charges And Fields

Question

A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s^–1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the e.m.f. developed between the centre and the ring.

Solution

Here,
Length of the rod, l = 1 m
Angular frequency of roation, ω = 400 s^–1Uniform magnetic field, B = 0.5 T
e.m.f =?

Note that linear velocity of one end of rod is zero and linear velocity of other end is (l ω).
Therefore,
Average linear velocity

v = \frac{0 + lω}{2} = l ω / 2 .

(∵ ν = rω)

Hence,

e = Blv = Bl \frac{(l ω)}{2} = \frac{{Bl}^{2} ω}{2} = \frac{0.5 \times 1^{2} \times 400}{2} = 100 V

Some More Questions From Electric Charges and Fields Chapter

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
b) Explain why two field lines never cross each other at any point?

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Electric Charges And Fields

Some More Questions From Electric Charges and Fields Chapter

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
b) Explain why two field lines never cross each other at any point?

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NCERT Sample Papers

Entrance Exams Preparation

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For Daily Free Study Material Join wiredfaculty

Electric Charges And Fields

Some More Questions From Electric Charges and Fields Chapter

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?b) Explain why two field lines never cross each other at any point?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
b) Explain why two field lines never cross each other at any point?