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Electric Charges And Fields

Question

Self-inductance of an air core inductor increases from 0.01 mH to 10 mH on introducing an iron core into it. What is the relative permeability of the core used?

Solution

Initial self inductance = 0.01 mH
Final self inductance = 10 mH

Therefore,
Relative permeabilty of the core is,

μ_{r} = \frac{L_{2}}{L_{1}} \Rightarrow μ_{r} = \frac{10}{0.01} = 1000 .