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Magnetism And Matter

Question
CBSEENPH12037823

A tangent galvanometer is set with its plane making an angle of 30° with the magnetic meridian. When a current is passed through 2 turns coil of radius 0.10 m, in the anti-clockwise direction, the compass needle shows a deflection of 30°. Calculate the strength of current passed. Take H = 0.32 x 10–4 T.

Solution

Number of turns, N = 2
Radius of the coil, r = 0.10 m
Deflection, θ = 30o 
H = 0.32 × 10-4

Before passing current, compass needle was along the direction of H.
On passing current, the needle shows a deflection of 30° (with H) under the combined effect of H and B.
Magnetic field due to current is in a direction perpendicular to the plane of the coil. 

As compass needle is inclined equally to H and B, as in fig.  



Therefore,
                B = H 

         μ0 N I2r = H 

                  I=2r Hμ0 N  = 2×0.1×0.32×10-44π×10-7×2  

                  I = 2.54 A