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Magnetism And Matter

Question
CBSEENPH12037822

The core of a toroid having 3000 turns has inner and outer radii of 11 cm and 12 cm respectively. The magnetic field in the core for a current of 0.70 A is 2.5 T. What is the relative permeability of the core? Take π = 3.14.

Solution
Number of turns of torroid, N = 3000
Inner radii, r1 = 11 cm
Outer radii, r2 = 12 cm
Therefore, mean radius, r =11.5 cm = 11.5 x 10–2 m
Magnetic field in the coil, B= 2.5 T
Current carried by the coil, I = 0.70 A

The magnetic field in the empty space enclosed by the windings of the toroid is given by
                   B = μ0nI              ...(1) 

where, n is the number of turns per unit length and I is the current.

If the space is filled by a core of permeability μ, then equation (1) is rewritten as :
                      B = μnI 

Hence,

Number of turns per unit length is,
              n = 30002π×11.5×10-2m-1 

Here, we have ignored the variation of B across the cross-section of the toroid and taken the radius of the toroid to be the mean of inner and outer radii.
          μ = BnI    = 2.5×2π×11.5×10-23000×0.7μ = 8.6 × 10-4T m A-1  

Relative permeability of core, μr = μ0μ0 = 684.7

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