Question
Each atom of an iron bar (5 cm x 1 cm x 1 cm) has a magnetic moment 1.8 x 10–23Am2.
(a) What will be the magnetic moment of the bar in the state of magnetic saturation.
(b) What will be the torque required to place this magnetised bar perpendicular to magnetic field of 15000 gauss?
Density of iron = 7.8 x 103 kg/m3
Atomic weight of iron = 56
Avagadro’s number = 6.023 x 1023 gm/mole
Solution
Here, volume of specimen,
Number of atoms per unit volume
For iron,
Therefore,
Total number of atoms in the iron bar
Saturated magnetic moment of the bar
Number of atoms per unit volume
For iron,
Therefore,
Total number of atoms in the iron bar
Saturated magnetic moment of the bar