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Magnetism And Matter

Question
CBSEENPH12037820

A circular coil of 100 turns and having a radius of 0.05 m carries a current of 0.1 A. Calculate the work required to turn the coil in an external magnetic field of 1.5 T through 180° about an axis perpendicular to the magnetic field. The plane of the coil is initially at right angles to the magnetic field.

Solution

Here,
Number of turns, N = 100
Radius of the coil, r = 0.05 m
Current carried by the coil, I = 0.1 A
External magnetic field, B = 1.5 T
θ is the angle between B and A of the coil.

θ1 = 0o and,θ2 = 180o 

Magnetic moment is given by, M = NIA 
                                    = n I (πr2) = 100 × 0.1 (3.14) (0.05)2  = 7.85 × 10-2 Am2 

Amount of work required to turn the coil in an external magnetic field,

W = -MB (cos θ2-cos θ1)      = -7.85 × 10-2 × 1.5 (cos 180° - cos 0°)W = 0.24 J

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