Question
If δ1 and δ2 be the angles of dip observed in two planes at right angles to each other and δ is the true angle of dip, then prove that
cot2 δ1 + cot2 δ2 = cot2 δ
Solution
Given, δ1 and δ2 are the angles of dip right angle to each other in planes.
δ is the true angle of dip.
If horizontal and vertical components of earth's magnetic field are represented by BH and Bv respectively, then
Let, δ1 be the (apparent) dip in a plane which makes angle θ with the magnetic meridian.
In this plane, the vertical component will be BV only but the effective horizontal component will be BH cos θ.
Therefore,
[ ]
...(i)
δ is the true angle of dip.

If horizontal and vertical components of earth's magnetic field are represented by BH and Bv respectively, then
Let, δ1 be the (apparent) dip in a plane which makes angle θ with the magnetic meridian.
In this plane, the vertical component will be BV only but the effective horizontal component will be BH cos θ.
Therefore,
[ ]
...(i)
Let, δ2 be the (apparent) dip in the second plane.
The angle made by this plane with the magnetic meridian will be (90° – θ).
Effective horizontal component in this plane is BH cos (90° – θ) i.e., BH sin θ.
The vertical component will be Bv only.
...(ii)
Squaring and adding equation (i) and (ii), we get
Hence proved.