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Magnetism And Matter

Question
CBSEENPH12037796

A magnet having a magnetic moment of 1.0 x 104 J/T is free to rotate in a horizontal plane where a magnetic field 4 x 10–5 T exists. Find the work done in rotating the magnet slowly from a direction parallel to the field to a direction 60° from the field.

Solution

Given,
Magnetic moment, M = 1.0 x 104 J/T 

 θ1 = 0°,   θ2 = 60° 

Magnetic field,  B = 4 × 10-5T 
Using the formula for work done, 

           W=-MBcos θ2 - cos θ1

              = -1.0 × 104 × 10-5 (cos 60° - cos 0°)= -0.412-1= 0.2 J.