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Magnetism And Matter

Question
CBSEENPH12037744

A monoenergetic (18 keV) electron beam initially in the horizontal direction is subjected to a horizontal magnetic field of 0.40 G normal to the initial direction. Estimate the up or down deflection of the beam over a distance of 30 cm. Given mass of electron 9.11 x 10–31 kg and charge on electron = 1.6 x 10–19 C.
[Note: Data in this exercise are so chosen that the answer will give you an idea of the effect of earth’s magnetic field on the motion of electron beam from electron gun to the screen in a T.V. set.]

Solution

Here,
Energy of the electron beam, E = 18 keV = 18 × 1.6 × 10-16J
Horizontal magnetic field, B = 0.40 G = 0.40 × 10-4T
distnace, x = 30 cm = 0.3 m 



As,
Energy, E = 12m v2 

  v = 2E/m 

In a magnetic field, electron beam is deflected along a circular arc of radius r, such that
 Beν = 2r r = mvBe      r = mBe2Em        = 1Be2E m        = 11.3 m   

In OCB,  

sin θ = xr
sin θ = 0.311.3 = 3113

y = r - OC    = r - r cos θ    = r(1- cos θ)    = r[1-1-sin2θ] 

By using binomial expansion,
                             y = r1-1-12sin2θy = r2. sin2θy = 11.32×3×3113×113×10  = 92260   = 3.98 × 10-3  4 mm.