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Magnetism And Matter

Question
CBSEENPH12037743

A sample of paramagnetic salt contains 2.0 x 1024 atomic dipoles each of dipole moment 1.5 x 10–23 J T–1. The sample is placed under a homogeneous magnetic field of 0.64 T, and cooled to a temperature of 4.2 K. The degree of magnetic saturation achieved is equal to 15%. What is the total dipole moment of the sample for a magnetic field of 0.98 T and a temperature of 2.8 K? (Assume Curie’s law)

Solution

Given,
Number of atomic dipoles, n = 2.0 x 1024

Magnetic dipole moment of each dipole = 1.5 x 10–23 J T–1 

∴ Total possible magnetic dipole moment of the sample, M = 1.5 x 10–23 x 2.0 x 1024
               = 30 J T–1

Magnetic field, B1 = 0.64 T

At temperature of 4.2 K, the magnetic saturation is 15%.
∴ Dipole moment achieved at 4.2 K = 15% of M 
Hence, 
 M1 = 30 × 15100      = 4.5 J T-1 

According to Curie's law, 
M  BT 

 M1M2 = B1T1×T2B2
 M2 = M1 × T1T2 × B1B2

Here, 
M1 = 4.5 JT-1,   T1 = 4.2 K,  T2 = 2.8 K  B1 = 0.64 T and B2 = 0.98 K

M2 = 4.5 × 4.2 × 0.982.8 × 0.64        = 10.335 JT-1 

is the magnetic dipole moment at 0.92 K .