Question
A closely wound solenoid of 800 turns and area of cross-section 2.5 x 10–4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?
Solution
Given,
Number of turns, N = 800
Area of cross-section, A = 2.5 x 10–4 m2
Current, I = 3.0 A
Magnetic dipole moment,
Putting values, we get
M = 800 x 3.0 x 2.5 x 10–4
= 0.6 JT–1
Magnetic field is developed along the axis of the solenoid. Therefore, solenoid acts like a bar magnet. The direction is determined by the sense of flow of the current.
Number of turns, N = 800
Area of cross-section, A = 2.5 x 10–4 m2
Current, I = 3.0 A
Magnetic dipole moment,
Putting values, we get
M = 800 x 3.0 x 2.5 x 10–4
= 0.6 JT–1
Magnetic field is developed along the axis of the solenoid. Therefore, solenoid acts like a bar magnet. The direction is determined by the sense of flow of the current.
