-->

Magnetism And Matter

Question
CBSEENPH12037715

A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 x 10–2 J. What is the magnitude of magnetic moment of the magnet?

Solution

Given,
Angle between magnetic moment and magnetic field, θ = 30°
External magnetic field, B= 0.25 T
Torque, τ = 4.5 x 10–2 J

Using formula

                τ = M. B sin θ

            M =τB sin θ    = 4.5 × 10-20.25 × sin 30°   

              m = 0.36 JT-1 

where, m is the magnetic pole strength.