Write the relation for current sensitivity and voltage sensitivity of a moving coil galvanometer? Using these relations, explain the fact that increasing the current sensitivity may not necessary increase the voltage sensitivity.

Solution

Current sensitivity, I_s = $\frac{θ}{I}$

Voltage sensitivity, V_s= $\frac{θ}{V}$

$= \frac{θ}{IR}$

$= \frac{Current sensitivity}{Resistance}$

where, $θ$ is the deflection produced.

The above relation implies, if current sensitivity increases as well as the resistance increases in same order, the voltage sensitivity will remain unchanged.

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Moving Charges And Magnetism

Write the relation for current sensitivity and voltage sensitivity of a moving coil galvanometer? Using these relations, explain the fact that increasing the current sensitivity may not necessary increase the voltage sensitivity.

Some More Questions From Moving Charges And Magnetism Chapter

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