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Current Electricity

Question
CBSEENPH12037569

A parallel combination of two cells of emfs E1 and E2 and internal resistance r1 and r2is used to supply current to a load of resistance R. Write the expression for the current through the load in terms of E1, E2, r1 and r2.

Solution

Given,
Emf of first cell = E1 
Emf of second cell = E
Internal resistances of two cell are r1 and r2 respectively. 
Load resistance = R 

Effective emf is given by, EeffE1r1 + E2 r2r1 + r2  

Effective internal resistance, reffr1 r2r1 + r2 

Now, the total resistance of the circuit would be the sum of load resistance and effective internal resistance. 

             Rtotal = R + reffR + r1r2r1+r2 
Current through the load will be the same as the current through the circuit. 
Thus, 
I = EeffRtotal  = E1r1 + E2r2r1 +r2R+ r1r2r1 + r2 = E1r1 + E2 r2R(r1+r2) + r1r2 

which is the required expression for the current through the load.